Find the LCM (Lowest Common Multiple) of two numbers

This program considers x and y as input.If either of the two number is 0 then the LCM is 0.For finding LCM,temporary variables x1 and y1 are used whcih stores the vaue of x and y respectively.Both the numbers x and y are compared with each other and the respective temporary variable is added in the smaller number.This process continous until the number are equivalent to each other.When both the numbers are equivalent then x is LCM of two numbers.

#include < stdio.h >
#include < conio.h > 

void main()
{
     int x,y,x1,y1;
    clrscr();
    printf("\nEnter two numbers :");
    scanf("%d %d",&x,&y);
    x1=x;
    y1=y;
    if(x==0 || y==0)
    printf("\n LCM is 0");
    else
    {
        while(x!=y)
        {
            if(x>y)
            y=y+y1;
            else
            if(x < y )
                x=x+x1;
        }
        printf("\n LCM is %d",x);
    }
}